Inkriql Posted November 6, 2019 Posted November 6, 2019 Pep Guardiola's Manchester City faces a new challenge in its eagerness to devote itself for the first time in its history, in a season in which it is achieving great results at European level and the illusion grows more and more. For the fourth date of the 2019/20 UEFA Champions League group stage, the English team visits Atalanta at the San Siro stadium, where they will try to take a key step towards the round of 16. After getting a great comeback against Southampton on Date 11 of the Premier League, the Citizens will try to get their fourth straight win in Italy in Group C of the main competition of clubs on the continent, where they march undefeated and with an ideal score. “Although it seems the opposite given the result, we saw in Manchester that Atalanta is a very good team. The last time we met the game was very even in the first half, ”Guardiola told the press conference before the game. English football defending champions won 5-1 at Etihad Stadium, to seal a record of three wins, with 10 goals in favor and only one against. A victory, moreover, would be a great boost for Manchester City in the face of their next match in the English league, as it will collide with Liverpool next weekend. “It's a great week for us because we come to Italy and face Atalanta and then we face Liverpool on Sunday. We want to qualify as soon as possible, ”Guardiola acknowledged. For its part, Atalanta, which has lost all three games in its UEFA Champions League premiere season, will play again without Colombian striker Duvan Zapata, but coach Gian Piero Gasperini still believes they can get a result. “For us this match represents an opportunity to remain in the competition. It will be a very tough game, but fortunately we start again with 0-0. Nobody likes to concede many goals, but we will remain true to our style in a prestigious stadium like San Siro, known throughout the world. With a positive result, we will stay in Europe, there is even the Europa League, ”said Gasperini. 1
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